How much energy is required to vaporize 2 kg of aluminum. The latent heat of vaporization for aluminum is 4730 kJ/kg.

How much energy is required to vaporize 2 kg of aluminum. The energy required to vaporize 2 kg of aluminum is 9460 kJ. Step 2: The mass of aluminum given is 2 kg. Step 4: Q = 2 \, \text {kg} \times 1930 \, \text {kJ/kg} Q=2kg×1930kJ/kg. Step 3: Substitute the values into the formula Q = m \cdot L_ {vapor} Q=m⋅Lvapor. Apr 30, 2020 · Thus, the energy required to vaporize 2 kg of aluminum is 2200 kJ. Jan 13, 2025 · We are also given the mass of aluminum, which is 2 kg. Use the formula $$Q = mL_ {vapor}$$Q = mLvapor to calculate the energy required. Step 1: The latent heat of vaporization for aluminum is 1930 kJ/kg. The mass of aluminum given is 2 kg. Click here 👆 to get an answer to your question ️ How much energy is required to vaporize 2 kg of aluminum? How much energy is needed to vaporize 2 kg of aluminum? - Answers Subjects > Science > Natural Sciences What information does the potential energy diagram reveal about a reaction? It shows whether the reaction is exothermic or endothermic. Solution Answer: The energy required to vaporize 2 kg of aluminum is 3860 kJ. What does a negative H tell about a reaction? The reaction is exothermic. 😉 Want a more accurate answer? Get step by step solutions within seconds. Keep in mind that this energy is specific to changing the state of aluminum from liquid to gas at its boiling point of 2450 °C. . The latent heat of vaporization for aluminum is 4730 kJ/kg. Let's plug the values into the equation: Q = 2 kg × 1100 kJ/kg Now we can perform the multiplication: Q = 2200 kJ Therefore, the energy required to vaporize 2 kg of aluminum is 2200 kJ. From the table, the latent heat of vaporization for aluminum is 1100 kJ/kg. ufdmz iubovowz yibunaow vnpdim knzg hipxcqk ibyt vovhdh ork kmgbe